Can you make CheckBoxes with the Button on the Leftt and Text on the Right ?

[MikeR]

Can you make CheckBoxes with the Button on the Leftt and Text on the Right ?

[rjolda]

HI Mike,
Where do you want to make them?  Forms?, Browses?  Anywhere?  Do you want to be more specific?  Do you want to do these in plain Net Talk or do you want to use css?
Ron

[MikeR]

I want to do it on a netwebform.
The form contains many fields some with long questions with a checkbox reply.
The default behaviour on a form is that all fields prompts and value and comments are aligned
So a form with a long question makes all the fields values move far right
I am happy to accomplish it in nettalk or using css
help me understand what options I have ?
 

[rjolda]

i Mike,
I am doing that with native NT.  Initially, I had a consultant help me and he did it in css by working around the NT css as custom css.  That was somewhat fragile so I deleted the custom CSS and did this in NT alone:
Checkbox  at left.   Description at right.  Now, I don't have to fudge css every time I want to play with it.
I have attached some screen pics to help explain.
Ron
 

[Alberto]

Wise, no prompt and using the comment.

[MikeR]

Thank you very much for this rjolda.
I am new to Nettalk14 and need to look at all the new options on the templates.

[rjolda]

Mike,
Templates have a LOT in them.  A lot of things are not what they seem to be.  You just have to ask questions and experiment! Incredible stuff is doable with NT and even more with NT and css.  I try to do as much in NT as I can.  My custom.css is very tiny.
Ron

[rjolda]

Mike,
This is a clearer example of having check on LEFT and text on right.  I have a screen shot of template ( Hide Prompt and put Text in COMMENT and SHOW comment only).
Ron

BTW - the Layout for this Form is TABLE ( not Grid or Flex)
Ron

[rjolda]

HI,
Also found that you can use the Check Box Tab for a check box and use the True Text and False Text to get the same result except the text is now inside the button !
Check box field is Byte - 0/1
Ron